here "a" has nothing to do with "b", it just copies the value of b, you mention as if they are…

Even though b goes out of scope, the memory is not immediately deallocated because a still owns it.
Memory Safety in C++ vs Rust vs Zig
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B Shyam Sundar
Osman Yasal
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Aug 12, 2024
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here "a" has nothing to do with "b", it just copies the value of b, you mention as if they are related in some sense but they are NOT.
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Written by Osman Yasal45 Followers
·22 Following
Parallel Computing | Performance tools | Digital Twins | Computer Vision | Image Processing | Deep Learning.
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